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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Dinesh khalmaniya 1
bond order= 1+ (total pi bonds/ total sigma bonds) here pi bonds = 2 and sigma bonds = 4 so 1 + 2/4 = 1.5
sir plz solve this
got it??
sir but
bond order = total bonds / resonanting structures
yes it also correct
you can draw resonating structures and calculate it
you can also calculate it by using the formula B.O = total bonds covalent bonds / surrounding atoms = 6/ 4 = 1.5
it is easy sir
btw sir I have drawn the resonationg structure but didn't got by that method pl, solve by that method plz
yes
shweta yha only two resonating structures possible he baki sbhi identical hogi
ik video main 6 bnate hue hain
...
..9 is total c-o bond
9/6 = 1.5
pr 2 hi different bnege baki identical hoge to koi mtlb nhi. ap bna skte ho pr mitake hone k chance jada he
ok sir
and thanku 🙂