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Finding difficulty in solving problems of percentage of s n p character
finding difficulty in solving problems of percentage of s n p character
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Keerthi
for this question how to find
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Suman Kumar Best Answer
Use this formula
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Dinesh khalmaniya 1
Answer: s-character is the contribution of sigma type bond in a hybridization: sp3 = 25% s-character, 75% p-character sp2 = 33% s-character, 66% p-character sp = 50% s-character, 50% p-character The more s-character a bond has, the stronger and shorter the bond is. Similarly, how do you find the percentage of a character s? Cos 120 => -1/2 = s/s-1 => -s+1 = 2s => s=1/3. Now % s character = (1/3 × 100)% = 33.3%. So it contributes 33.3% s orbital from 100% to form new hybrid orbital. And other 66.7% should be contributed by p orbital.
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check this example
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Suman Kumar
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