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For a 0.1 m aqueous solution of lysine, the ph at which it carries no net charge is (pk values for: a-carboxylic group = 3.1, a-amino group 8.0, &-amino group =
For a 0.1 M aqueous solution of lysine, the pH at which it carries no net charge is (pK values for: a-carboxylic group = 3.1, a-amino group 8.0, &-amino group = 10.8) For a tha fallaw
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Abhijeet Gaurav![best-answer]()
The Net Charge for Lysine to be equal to Zero is when it acheives pI. Since Lysine is an Positive charge containing Amino acids in it's side chain so it can release an an H+. Now as per the Lysine it's pKa would be =( 10.8 + 8) /2 = 9.4. So answer would be 9.4 approaximately. The image below given is of a standard amono acids containing R group NH3+. So it can be taken as reference & based similarily the pKa of Lysine can be calculated which equals 9.4 .