Karnan posted an Question
December 07, 2020 • 19:49 pm 30 points
  • IIT JAM
  • Chemistry (CY)

For a cell reaction pb(s) + hg2cl2(s) pbcl2(s) + 2hg(), oe ot is 1.45 x 10-1 vk-1. the entropy change (in j molkl) for the reaction is [given 1 f 96500 c mol]_

For a cell reaction Pb(s) + Hg2Cl2(s) PbCl2(s) + 2Hg(), OE OT is 1.45 x 10-1 vK-1. The entropy change (in J molKl) for the reaction is [Given 1 F 96500 C mol]_

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  • D s kumar best-answer

    change in entropy = 27985 J /K/mol.. solution is attached...

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    Priyanshu kumar

    27.985 Jk^-1mol^-1

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    verify the value given for variation of EMF with temperature. ..you have used 1.45 ×10^- 4 ...but is given as 1.45 ×10^ -1...so the Chang of entropy value is 27985 j/k/mol..

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