Saurabh Asked a Question
December 15, 2020 4:42 pmpts 30 pts
for an isothermal process how delta E is zero? and why in the first operation of carnot cycle we are taking delta e =0.
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  • Suman Kumar Best Answer
    For ideal gas only delta E will be zero . As delta E is a function of temperature for ideal gas. Since the process is isothermal means delT is zero so delE will also be zero
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    Saurabh
    didn't got it in isothermal del T=0 but how delE =0?
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