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For cfse, if a molecule have cfse -1700 cm- & if we give energy exact opposite ie. +1700 then what will happen, do legand go away?
for cfse, if a molecule have cfse -1700 cm- & if we give energy exact opposite ie. +1700 then what will happen, do legand go away?
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Dinesh khalmaniya 1
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Dinesh khalmaniya 1
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The crystal field stabilisation energy (CFSE) is the gain in the energy achieved by preferential filling up of orbitals by electrons. It is usually less than or equal to 0. When it is equal to 0, the complex is unstable. The magnitude of CFSE depends on the number and nature of ligands and the geometry of the complex. so the The crystal field stabilization energy (CFSE) is the stability that results from ligand binding. if you will give energy in equal amount to cfse, it will destabilize complex. so no longer complex will exist
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then, do all d orbital get same energy
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yes, no splitting occur mean no metal ligan bonding
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Suman Kumar Best Answer
No Anand No. What is CFSE?
Let's take two examples
Ca(H2O)6 ²+ & Sc(H2O)²+. Here is two complex. please give my answer First which has higher hydration energy?
Hint : Ca²+ is d0 configuration while Sc²+ is d1 configuration
can you Answer Anand?
1 min
sc will have higher energy na,
Yes Ofcourse. Can you give reason?
for ca, all vacant orbital are availabe
No The reason is simply CFSE. It is the extra stabilisation that d-block has.
Due to presence of d - eletron it undergo splitting. Splitting ke karan hi to CFSE aayi hai na.
Agar splitting nahi hota to CFSE kaisa? lekin bond to Ca ne bhi banaya hai to Sc kyo nahi banayega?
what hybridization do both will have, ?
if all legands will go in d orbital, both will hve cfse 0
sp3d2 & d2sp3
sir lekin agar ca is 2+ then its whole d orbital is empty na
Yes then what happen
sp3d2 kaise, isme to d orbital 4d hai, pehle hi 3d ke empty hai to wo kaise bharenge
let me see, after some time i will msg you