Shristy posted an Question
August 19, 2020 • 20:47 pm 30 points
  • IIT JAM
  • Chemistry (CY)

For the following reaction 2mno+5h,c,04 +6h-2mn + 8h;0+10co2 e'mno /mn*) = +1.51 v and e" (co/h,c,04) = -0.49 v. at 298 k, the equilibrium constant is: + (a) 10

For the following reaction 2MnO+5H,C,04 +6H-2Mn + 8H;0+10CO2 E'MnO /Mn*) = +1.51 V and E" (CO/H,C,04) = -0.49 V. At 298 K, the equilibrium constant is: + (a) 10300 (b) 10338 (c) 1038 (d) 10833

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    Priyanshu kumar Best Answer

    check this shristy👇

    cropped5168631424593753255.jpg
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    You have to first find E° of the cell and proceed accordingly

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    got this shristy??

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    how n=10 comes ???? will it be n= 5

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    shristy for one Mno4- to Mn2+ it is +5 but for 2Mno4- it is 10 na

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    now clear??

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    ok sir

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