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Vijay Singh chauhan Asked a Question
April 6, 2021 3:10 pmpts 30 pts
  • IIT JAM
  • Mathematics (MA)

For the value of f(0) = 3, f()=6, f(2) = 11, f3) = 18 and f(4) = 27, the funetion f(x) will be (a)x* +3x * 3 (c)x* + 2x+3 (b)2x +3x +1 (d)x- 2x-1

For the value of f(0) = 3, f()=6, f(2) = 11, f3) = 18 and f(4) = 27, the funetion f(x) will be (a)x* +3X * 3 (c)x* + 2x+3 (b)2x +3x +1 (d)x- 2x-1
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  • Deepak singh thankyou
    Refer attached option c
    • cropped8340854693191503511.jpg
    Likes(1) Reply(0)
  • Piyush thankyou
    option C is correct.
    Likes(1) Reply(0)
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