Shweta Thakur posted an Question
January 06, 2021 • 04:51 am 30 points
  • IIT JAM
  • Chemistry (CY)

For this question i firstly thought thatif reactant exceed product than product has to be unstable in order to proceed reaction backward so that's why i asked u

F) (CD,,CH+ (CH,,C (CD C+ (CH,,CH ()CH-C=C-H +NH,CH-C=C+NH, +NH,

2 Answer(s) Answer Now
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    Dinesh khalmaniya 1 best-answer

    option A if stability of product is more than reactant than concentration of product will be more than reactant hence K > 1 if stability of reactant is more than product than concentration of product will be less than reactant hence K < 1. in case of A, there is +H of CH3 more than CD3 so reactant will be more stable than product so K < 1

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    I thought stability hmen only product ki dekhni hai

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    yes

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    product ki reactant se compair kr lo baat to ek hi he na

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    fr Aapne wrong kyun bola

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    kha bola

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    baat to whi he na, reactant ki stability jada he mean product ki km he or product ki stability jada he mean reactant ki km he

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    I m talking about this .....yhan mane only product Likha tha u said aise compare ni kr skte

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    ohh sorry me is question ki baat kr rha tha

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    apne complete question nhi diya tha na,, all the options are different

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    yha only reactant and product me compair krege na ki in four products me

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    thanku sir

  • comment-profile-img>
    Priyanshu kumar Best Answer

    if K>1 products is favoured...if K<1 reactants is favoured...if K=1 neither reactants nor products is favoured

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    option A should be correct

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    why how

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    what I have thought is that correct

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    that we have to find least stable species

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    wait shweta explaining

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    okokok

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    In option A reactant side is favoured as hyperconjugation of ch3 is more than cd3..so reactant side carbocation is more stable than product side

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    So k is less than unity for option A

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    got this shweta?

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    no sir

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    yeh kl discuss kren

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    ok shweta

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    good night sir

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    good ni8

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    Thanku sir

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