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Reshav posted an Question
September 06, 2020 • 04:29 am 30 points
  • IIT JAM
  • Chemistry (CY)

Given: aan= 40.668 kj mol a jg mass of cu at temperature of 393 k is placed contact with a 100 g mass ot copper at a temperature of 303 kin a thermally insulate

Given: Aan= 40.668 kJ mol A Jg mass of Cu at temperature of 393 K is placed contact with a 100 g mass ot copper at a temperature of 303 Kin a thermally insulated container. Calculate ASoal for the reversible proCEss Use a value of 0.4184 J gl K for the specific heat capacity of Cu. 38 One mOle of helium is mixed with 2 mol of neon, both at the same temperature and pressure.

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    Priyanshu kumar Best Answer

    check this dear

    cropped6937336445769378136.jpg
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    got this reshav??

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    sir delta S total for reversible processes clzero nhi hota hai kya

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    Change in entropy for a reversible process is not necessarily zero. For a reversible process dS=dQ/T In general, Change in entropy=dQ/T + Entropy generation (due to irreversibility) This entropy generation is path dependent (may be +ve/-ve/zero), for reversible path it is zero. Therefore, 1. For a reversible process, Entropy change is zero iff it is adiabatic. 2. For any process (reversible/irreversible), Entropy change may be +ve/-ve/zero.

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    Means for reversible process entropy change is zero only when process is adiabatic

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    ok thankyou

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    Reshav

    sir answer .... pls

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    Zero na Reshav

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    how to calculate entripies of the system and surroundings please tell me in this concept iam doing mistakes....

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    no

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