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###### Arun posted an Question
December 30, 2021 • 11:42 am 30 points
• IIT JAM
• Physics (PH)

# Given an equation of incident electric field equation how can we know whrther it is subjected to half wave plate,how can we know wether its rotation has changed

given an equation of incident electric field equation how can we know whrther it is subjected to half wave plate,how can we know wether its rotation has changed or not

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• ##### Isha lohan 1

A half wave plate tends to shift the polarization direction of linearly polarized light. When considering a linearly polarized light, a half wave plate refers to the effect of the half wave plate that rotates the polarization vector at an angle of 2θ. However, if we consider an elliptically polarized light, the half wave plate shows the effect of inverting the handedness of the light. To check the rotation we use an instrument Polarimeter. Using such other instruments we can measure the amount of rotation of light.

ask if any further doubt

I mean suppose I have two electric fields equations given as E1=E0(x+y)Cos(wt+kz) and final field Expression as E2=E0(x-y)Cos(wt+ kz) and we need to identify what is the phenomenon taking place, the answer was that the field was subjected half wave plate,now I want to know how can one conclude whether there is a change in handedness of polarized light just by looking at these equations

you see here only y component has reversed its direction rest all is same. As i have mentioned that for linear polarised, wave rotates by 2 theta. Incoming wave has amplitude Eo(x cap + y cap) it means it enters with theta = 45. so it rotates by 90 degree. see in diagram.

You asked a good question. Not most students think deep in this direction in optics.

If you want to know the derivation of how half wave plate rotate linear polarised light by 2 theta, and how other plates behave and further deeper details. The best reference is Optics book by Ajoy Ghatak, Polarisation Chapter, Wave Plates Topic. There you will find derivation of all type of situation.

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