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Jhulan Haldar posted an Question
October 09, 2021 • 05:06 am 1 points
  • IIT JAM
  • Mathematics (MA)

Given s and s, where s:1-1+1-1+1+...= t1 1 sa 1-2+2-2+... then. 1+2 (a) s, is true but s, is false (b) s is false but s, is true (c) both s and s, are true

Given s and s, where S:1-1+1-1+1+...= t1 1 Sa 1-2+2-2+... Then. 1+2 (a) s, is true but s, is false (b) s is false but S, is true (c) Both s and s, are true

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    Arpan pal

    option a is false because if S1=1-1+1-1+...=1=1 , since S1=1-(1-1+1-...)=1 Again S1=(1-1)+(1-1)+...=0 so option a is false . Option b is correct because we know that S2=1-2+2^2-2^3+2^4-...=1/(1+2) So S1 is false and S2 is true.

  • Anonymous User best-answer

    A S1 xn=(-1)^n if n is even then S1is 1 if n is odd then S1 is -1 S2 (1+x)^-1 =1-x+x²-x³+...... if |x|<1 so S2 wrong

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