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Jhulan haldar Asked a Question
October 8, 2021 11:36 pm 1 pts
Given s and s, where S:1-1+1-1+1+...= t1 1 Sa 1-2+2-2+... Then. 1+2 (a) s, is true but s, is false (b) s is false but S, is true (c) Both s and s, are true
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option a is false because if S1=1-1+1-1+...=1=1 , since S1=1-(1-1+1-...)=1 Again S1=(1-1)+(1-1)+...=0 so option a is false . Option b is correct because we know that S2=1-2+2^2-2^...