Given s and s, where S:1-1+1-1+1+...= t1 1 Sa 1-2+2-2+... Then. 1+2 (a) s, is true but s, is false (b) s is false but S, is true (c) Both s and s, are true
option a is false because if S1=1-1+1-1+...=1=1 , since S1=1-(1-1+1-...)=1
Again S1=(1-1)+(1-1)+...=0
so option a is false .
Option b is correct because we know that
S2=1-2+2^2-2^...