Jhulan haldar Asked a Question
October 8, 2021 11:36 pmpts 1 pts
Given s and s, where S:1-1+1-1+1+...= t1 1 Sa 1-2+2-2+... Then. 1+2 (a) s, is true but s, is false (b) s is false but S, is true (c) Both s and s, are true
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  • Arpan pal
    option a is false because if S1=1-1+1-1+...=1=1 , since S1=1-(1-1+1-...)=1 Again S1=(1-1)+(1-1)+...=0 so option a is false . Option b is correct because we know that S2=1-2+2^2-2^...
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  • Navdeep goyal 1 thankyou
    A S1 xn=(-1)^n if n is even then S1is 1 if n is odd then S1 is -1 S2 (1+x)^-1 =1-x+x²-x³+...... if |x|<1 so S2 wrong
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