Given the matrix

if any doubt then ask..

in the above example AM is not equal to GM also .. result- A matrix is diagonizable iff it has n eigenvalues and AM= GM of each eigenvalues.. this result holds in both real and...

see, this symmetric complex matrix is no diagonizable.. so, A symmtric matrix may not be diagonizable.

see attached, i have mentioned how to find AM and GM

see , it may help u

Similar question has been asked in CSIR NET Dec 19 in part C

the correct options are 1,2, 3,4

see the attachment

see