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Since the order of a permutation is the least common multiple of the lengths of its cycles the permutations of order 5are exactly the 5 cycles. Once these have been selected there are 6! ways to order them inside the brackets. out of these ways to write them there are groups of 5 that represent the same permutation but are just rotated. Thus there are 6!/5=144 elements of order 5in A6
I didn't understand pls try again in a different way.
To find calculate 5 order permutations we calculate 5 cyclic permutations. we have 6 elements.we can making 5 cyclic permutations from 6 elements with ways 6! each 5 cyclic permutations repeat time. so number of element of order 5 is 6!/5=144