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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Shrigandha posted an Question
May 06, 2021 • 22:41 pm
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30 points
30 points
- IIT JAM
- Chemistry (CY)
H(9)+ cl(o) ag is-262 kj. calculate the equilibrium sol ag = -262000 j =- 2.303 rt log k 630oo 4s 1717 +262000 log k 2.303x8.314 x 298 s 70s.8 +82 ctrolysis =45
H(9)+ CL(o) AG is-262 kJ. Calculate the equilibrium Sol AG = -262000 J =- 2.303 RT log K 630oo 4s 1717 +262000 log K 2.303x8.314 x 298 S 70S.8 +82 ctrolysis =45.918 The pe trodes Cu2 | Cu and Ag | Ag are 0.337 V and 0.7rolysis o helectroly K = 8.279 x 1045 O 337 and . verted ire The standard electrode potentials of the electr VWhat would be the concentration of Ag: in a both the metals can be deposited together silver and copper do not dissolve among themseves Ex. and bouards g in a solution containing O.06 M of Cu ion such t dation e mber) er ? Assume that activity coefficients are unity and Sol The individual reactions are Cu2+ 2e Cu(s) and Ag +e Ag(s) The electrode potentials given by Nernst equation 1 0.0591, CU E(Cu Cu) = E° 2 nort@eduncle.com | Call Toll Free :1800-120-1021
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Shrigandha
I didn't understand how can we get 0.301 first step