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Anuradha posted an Question
June 07, 2020 • 18:51 pm 30 points
  • IIT JAM
  • Chemistry (CY)

H-c=c-h 1nanh2 (excess) 2. haco (2eq) 1. h2/pd/baso4b >a fo/h° 3. mcpba

H-C=C-H 1NaNH2 (excess) 2. HaCO (2eq) 1. H2/Pd/BaSO4B >A Fo/H° 3. mCPBA

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