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Prerna Chaudhary posted an Question
September 27, 2021 • 23:29 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Hgafrvnmdibgvfkibvbdojbgjd

hgafrvnmdibgvfkibvbdojbgjd a lgcehhjnbs kokilydkllbab in

1 Answer(s) Answer Now
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  • Anonymous User Best Answer

    (x,y,z) tands to (0,0,0) along the curve y=mx,z=nx (x,y,z) tands to (0,0,0) mnx³/x²(1+m²+n²)= (x,y,z) tands to (0,0,0) mnx/(1+m²+n²)=0 if limit are same for any two different curve which passes through the orgin then limit exist and same is its limit

    cropped957613199102034766.jpg
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