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Anonymous User Best Answer
(x,y,z) tands to (0,0,0) along the curve y=mx,z=nx (x,y,z) tands to (0,0,0) mnx³/x²(1+m²+n²)= (x,y,z) tands to (0,0,0) mnx/(1+m²+n²)=0 if limit are same for any two different curve which passes through the orgin then limit exist and same is its limit