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Anonymous User Best Answer
f(x)=ax²+bx+c f'(x)=2ax+b f"(x)=2a f(0) =2 f'(0)=-3 f"(0) =4 so f(x)=2x²-3x+2 f(x)dx=[2x³/3-3x²/2+2x] =4/3+4 =16/3 b