A. Sara Banu posted an Question
August 15, 2021 • 19:13 pm 5 points
  • IIT JAM
  • Mathematics (MA)

How c1e power - 2asin inverse of x came..................................

loga = -2a sin'x x+log(1-x*)+ log c, 2 Or, ay(1-x) = C,e 2a sin "x dv C.e-2a sin'x dx 1-x*) O = 2a sin X +C2 Integrating, V = e 2a sin'x 2a Therefore the required CS is y=ve* =-easin" asinx 2a sinxC2e Ge y= e-asinx asin'x f emoval of the

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  • Priyadarshan Choursiya best-answer

    wrong alpha = c1.exp(arcsin...). (1-xx)^0.5 is the correct

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