Neha posted an Question
May 31, 2020 • 05:07 am 30 points
  • IIT JAM
  • Mathematics (MA)

How did we get this step?

U n+1)! Un+1 (a+nx)" {a +(n+1)x)n1 (n+1)x} (a+nx"(n +1) Now, n! nx" (a/nx + 1)"n(1 + 1/n) (n+1)x*{a/(n+1)x + 11

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    Ruby negi best-answer

    see this... only they take common xn from numerator and x(n+1) form denominator...

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    How will we get x^n in the last step?? shouldn't it be only X?

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    yeah, sorry for mistake... you are right

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