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Snehasish Ghosh posted an Question
July 09, 2020 • 04:29 am 30 points
  • IIT JAM
  • Physics (PH)

How is the limit choosen in this question since it is given that the centre of cube is at origin so why is not the lower limit 0?

2 Answer(s) Answer Now
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  • comment-profile-img>
    Ravi prakash yadav

    while doing the surface integrals limits of the integration are decided by the boundary of the surface. It has nothing to do with where the centre lies.

  • comment-profile-img>
    Chandra prakash

    dear listen to be carefully.....this coordinates axis is in centre of cubic axis see again

    eduncle-logo-app

    Sir, I got it..Thank you

  • comment-profile-img>
    Chandra prakash

    dear plz read again this que carefully and think...

  • comment-profile-img>
    Chandra prakash best-answer

    dear it's not start at origin see carefully

    eduncle-logo-app

    Yes sir,but the question says it has centre at origin

    eduncle-logo-app

    dear see diagram also

  • Mahak

    here the centre is origin but cube is equally divided on both sides of origin and given total length of side of cube is a so a/2 on right of origin and a/2 on left of origin

    eduncle-logo-app

    Ma'am, how did u know that the cube is equally divided on both sides of origin?

    eduncle-logo-app

    From the figure, it does not look like that

    eduncle-logo-app

    here origin is at centre of cube

    eduncle-logo-app

    if origin is at one corner then limit is 0 to a but here origin is at centre of cube

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