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Snehasish Ghosh posted an Question

July 09, 2020 • 04:29 am

30 points

IIT JAM
Physics (PH)

How is the limit choosen in this question since it is given that the centre of cube is at origin so why is not the lower limit 0?

2 Answer(s)

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Ravi prakash yadav

while doing the surface integrals limits of the integration are decided by the boundary of the surface. It has nothing to do with where the centre lies.
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Chandra prakash

try to visualize
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Chandra prakash

dear listen to be carefully.....this coordinates axis is in centre of cubic axis see again
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Sir, I got it..Thank you
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Arzoo Best Answer

See the attachment.
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Feel free to ask again
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thank you so much sir,I got it now
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Chandra prakash

dear plz read again this que carefully and think...
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Chandra prakash

dear it's not start at origin see carefully
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Yes sir,but the question says it has centre at origin
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dear see diagram also
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M
Mahak

here the centre is origin but cube is equally divided on both sides of origin and given total length of side of cube is a so a/2 on right of origin and a/2 on left of origin
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Ma'am, how did u know that the cube is equally divided on both sides of origin?
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From the figure, it does not look like that
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here origin is at centre of cube
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if origin is at one corner then limit is 0 to a but here origin is at centre of cube
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T