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Anjali posted an Question
December 21, 2020 • 02:23 am 30 points
  • IIT JAM
  • Chemistry (CY)

How many elements would be in the second period of the periodic table if the spin quantum 1 ,0, or + numbers could have the value,0, or +?

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    Lingareddy 1

    Number of orbit in second period (n) =2 and orbitals (n2) =4 Since, possible values of spin quantum number are +21​,0,−21​  i.e. 3.  Therefore, each orbital can occupy 3 electrons with different spin and a total of 4×3 i.e. 12 electrons in the second period. or n=2 l=0 m =0 s= 1/2, 0, -1/2 l=1 m=0 s= 1/2, 0, -1/2 l=1 m=1 s= 1/2, 0, -1/2 l=1 m= -1 s= 1/2, 0, -1/2 Total 3+3+3+3 =12

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    Dinesh khalmaniya 1 Best Answer

    12 elements

    cropped8929912871194408214.jpg
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    got it??

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    check this simple solution

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    generally one orbitals have two electrons which have two spins +1/2 and -1/2 but in this question 1 extra spin is given ie., 0 so total elwctrons in one orbital will be 3

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    here 2s and 2p includes total 4 orbitals so total elwctrons will ne 4 ×3 = 12

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    got it now?

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