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Lingareddy 1
Number of orbit in second period (n) =2 and orbitals (n2) =4 Since, possible values of spin quantum number are +21,0,−21 i.e. 3. Therefore, each orbital can occupy 3 electrons with different spin and a total of 4×3 i.e. 12 electrons in the second period. or n=2 l=0 m =0 s= 1/2, 0, -1/2 l=1 m=0 s= 1/2, 0, -1/2 l=1 m=1 s= 1/2, 0, -1/2 l=1 m= -1 s= 1/2, 0, -1/2 Total 3+3+3+3 =12