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Shweta Thakur posted an Question

April 26, 2021 • 21:45 pm

30 points

IIT JAM
Chemistry (CY)

How many molecules are there in 0.031 moles of nh3

how many molecules are there in 0.031 moles of nh3 sjsgmgs gsnafntwj

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A
Amol ashok pawar

Molar mass= N*1 + H*3 =14*1 + 1*3 =14+3 =17 It means, 1 mole of NH3=6.023 *10^23 0.031 moles of NH3=0.031 *6.02x10^23 =0.186*10^23
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sir divide hona chahiye
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because Jada ki Di hai km ki poochi hai
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ye example dekho.....
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it's like for one quantity we have 6.02x10^23 so for 0.031 we need that many amount so we cross multiply and get the value for 0.031
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Dinesh khalmaniya 1

Avogadros constant: 1 mole = 6.02x10^23 molecules/particles Therefore, .031 moles = .031 x 6.02x10^23 = 1.86x10^22
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sir pta ni mujhe confusion kyun ho ri hai
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kha confusion he
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sir agt 1 ki value Di Hoti hai km ki poochi Hoti hai to divide hota
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.....
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sir
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yha unit conversion nhi ho rha he.. apne unit conversion ka example liya he
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let take an example you have one dozens banana then how much banans in 0.5 dozens??? 0.5×12 = 6 ??
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A
Achyut ranjan gogoi

u know that the avogadro number is equal to 6.022 * 10^23 per mole . in 0.031 mole of NH3 the molecules present is equal to 0.031*6.022*10^23 molecules = 1.8 * 10^22 molecule is present.
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