30 points
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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Mathematics (MA)
How option d why not a ??
how option d why not a ??. . .. . . . .. . . . . . .. . . .
3 Answer(s)
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Anonymous User
you are thinking wrong direction because it will not equal to (0,2) . it will be subset of Q
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Anonymous User
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because the set of rational number is neither open set nor a closed set
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Deepak singh 1 Best Answer
Refer attachment
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sir but ur reasoning may be incorrect in few question...
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sir pls once see
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am i right sir...i mean is my example true?
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you are absolutely correct ..
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you taken example of uncountable set . Mine explanation/result is on countable..
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You can think in this way also that , Since Q is countable then its subset will also be countable . And we know countable set can't be open . So given set is not open .
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feel free to ask again
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i got ur logic sir..thanks a lot sir
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Anonymous User
visit through this link. https://youtu.be/vJD0f0iC6Vg
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Anonymous User![best-answer]()
because in (0,2) there are infinite irrational numbers. so if u are taking the intersection with Q then u can't take those irrational numbers . So u should skip those points from (0,2)