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Jeremy C. Zodinliana posted an Question
November 07, 2021 • 02:24 am 30 points
  • IIT JAM
  • Physics (PH)

How the value come 0.0012 and others

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    Jeremy c. zodinliana

    are u sapna ..topper iit jam 2021 about top 30

  • Sapna Best Answer

    Here there are corresponding terms given in terms of x and x=0.1 1st term is 2.3o26 x = 2.3026(0.1)=0.23026 2nd term 2.65095 x^2 = 2.65095 (0.1*0.1)= 0.0265095 rounding off to 5 terms then we can write it 0.02651 3rd term 2.0347 x^3 = 2.0347(0.1*0.1*0.1) = 0.0020347 again rounding off will give 0.00204 Similarly, 4th term is 1.17126 x^4 = 1.17126 (0.1*0.1*0.1*0.1) = 0.000117126 again rounding off to 5 terms we get 0.00012

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