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Astha Pandey posted an Question
January 24, 2021 • 20:47 pm 30 points
  • IIT JAM
  • Biotechnology (BT)

How this keq has been calculated here ? whole question is attached below. plz help.

(29.6) We have, AG-2.303 RT log K eq 1x10 =-2.303 x 8.314 x 310 x log 0.01 = - 5935.6 x log(1 x 10-5) = 5935.6x5 29,678 J/mol =29.6 kJ/mol

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    Astha pandey

    plz explain this also. How 7/5 came??

    cropped1088301802037962614.jpg
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    In scientific calculator you can calculate this value or this value is given in your question

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