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Anonymous User Best Answer
f(0)=0 f(1)=3 f(2)=6=0 so f is not homomorphism
sir but its answer is not homomorphism..
sir f is defined from Z3 to Z6 so 6 cant divide 3 so as per me because of that its not homomorphism
check now sorry
sir what u wanted to show by f(0)=0 f(1)=3 f(2)=6=0 ..i did not understood ..please can u once explain
image of 0 and 2 are same.so mapping not exist
definition of mapping each element has unique image but not here
understand
yes sir understood ..