Anku 1 Asked a Question
December 19, 2021 8:05 pmpts 30 pts
how to solve pls once show steps.... . . . . . . . . . . . . . . . . . . . . . . . . . .
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  • Navdeep goyal 1
    4 order but no cyclic
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  • Viksha garg thankyou
    (Z⊕Z)/⟨(2,2)⟩ is infinite. You can embed Z via k↦(k,0) (and in other ways) into it. The quotient is not cyclic, because it contains elements of finite order, (1,1)for example. Pro...
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  • Viksha garg Best Answer
    check attachment
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