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December 19, 2021 8:05 pm 30 pts
how to solve pls once show steps.... . . . . . . . . . . . . . . . . . . . . . . . . . .
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• Navdeep goyal 1
4 order but no cyclic
• Viksha garg
(Z⊕Z)/⟨(2,2)⟩ is infinite. You can embed Z via k↦(k,0) (and in other ways) into it. The quotient is not cyclic, because it contains elements of finite order, (1,1)for example. Pro...