Anku posted an Question
January 11, 2022 • 12:06 pm 30 points
  • IIT JAM
  • Mathematics (MA)

How to solve pls once show steps..

how to solve pls once show steps... . . . . . . .. . . . . . . . . . . . . .

2 Answer(s) Answer Now
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  • Anonymous User best-answer

    each gi is elements of order 2 for all I = 1 to n-1 so each element inverse itself . remaining gn is also inverse itself others wise order of G more then n . we know if every non identity element of G is of order 2 then G is an abelian so option A

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    Sonu saini Best Answer

    answer is A .....since every element is self inverse remaining only one element so this element must be of order 2(self inverse ) ....and if every element is of order 2 ....or if every element is self inverse then that group is always abelian .

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