Anku Asked a Question
August 17, 2020 1:36 pmpts 30 pts
how to solve pls show steps.. . . . . . . . . .. . . . . . . .
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  • Anuj s. Best Answer
    it is a cyclic group under multiplication and every cyclic group is abelian here 3 is generator
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    Anuj s.
    any doubt?
  • Deepak singh thankyou
    see attached
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    Anku
    thanks a lot sir
  • Deepak singh
    any doubt then ask
    Likes(1) Reply(0)
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