Madhu posted an Question
May 17, 2020 β€’ 03:43 am 30 points
  • IIT JAM
  • Mathematics (MA)

How to solve these kind of questions...

how to solve these kind of questions... pls do answer

3 Answer(s) Answer Now
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  • Madhu

    hey....pls do say how to find right hand and left hand limit....confused to solve..πŸ˜’πŸ˜’

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    see the attachment i have posted. may be it would help you

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    ok

  • Anonymous User

    @Arzoo ,you are right when x tends to zero from right then it's zero other cases goes to infinity,( Actually in my solution some typo mistake in place of zero it should be zero from right.)

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    πŸ‘

  • Anonymous User best-answer

    see.

    cropped8242801723216005922.jpg
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    Sir i think, In 4th there would be two cases. We can't say simply that e^(-1/x) approaches to zero.

  • comment-profile-img>
    Arzoo

    See the attachment

    cropped9011578223222010130.jpg
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    how did we get second step in 1st line..

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    limit x tends to 0...then x by e power -1/x +1

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    divide numerator and denominator by e^(1/x)

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    πŸ‘πŸ‘...arzoo pls do say how to find continuous and differentiable which I posted...or do and show any one example

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