Madhu Asked a Question
May 16, 2020 10:13 pmpts 30 pts
how to solve these kind of questions... pls do answer
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  • Madhu
    hey....pls do say how to find right hand and left hand limit....confused to solve..😒😒
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    Arzoo
    see the attachment i have posted. may be it would help you
  • Anonymous User
    @Arzoo ,you are right when x tends to zero from right then it's zero other cases goes to infinity,( Actually in my solution some typo mistake in place of zero it should be zero fro...
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    Arzoo
    👍
  • Arzoo thankyou
    See the attachment
    • cropped6351496592238258072.jpg
    • cropped4719015370094646068.jpg
    Likes(0) Reply(0)
  • Arzoo
    See this attachment
    • cropped8105222400894367760.jpg
    Likes(0) Reply(0)
  • Anonymous User thankyou
    see.
    • cropped8242801723216005922.jpg
    Likes(0) Reply(1)
    Arzoo
    Sir i think, In 4th there would be two cases. We can't say simply that e^(-1/x) approaches to zero.
  • Arzoo Best Answer
    Attachment 2
    • cropped1026570812400687724.jpg
    • cropped5072640023543425107.jpg
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  • Arzoo
    See the attachment
    • cropped9011578223222010130.jpg
    Likes(0) Reply(4)
    Madhu
    how did we get second step in 1st line..
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