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Sourav posted an Question
August 26, 2020 • 19:50 pm 30 points
  • IIT JAM
  • Chemistry (CY)

I don't know how to calculate this?

4. The vałue of 'n' for the following molecule according to Huckel's rule is : (a) 16 (b) 4 (o)3 (d) 14

2 Answer(s) Answer Now
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    Priyanshu kumar best-answer

    4n+2=14

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    n=3

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    option C is right

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    how

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    check this sourav 12 pi and 14 pi system

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    Middle one pi bond is not count for aromaticity...

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    got this sourav??

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    sir ye wale samjhado

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    sourav these are planarity and non planarity case...

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    ratna hai kya.. samjh mai nahi arha kaun planar hai aur kaun non palnar?

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    wait let me check for best video for u...ye to diagram se pta chal hi jayega bt fr bhi more detail...let me check any video

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    https://youtu.be/IWcRwMO9e4k check this Saurav....bdw when this type comes na here the middle hydrogen having vanderwaal repulsion ..due to this they goes out of plane and rest remain in the plane...so in 1st case it is aromatic as planarity is maintained...but in second case there is non planarity so non aromatic ...

  • Suman Kumar

    option C is correct

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    Here see this

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    Circled double bond is not a part of conjugation

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    if it is not a part of conjugation, then how it is aromatic?

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    it follows HUCKEL RULE. it has 14 eletron. so 4n +2 is satisfied

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