Shweta Thakur posted an Question
August 29, 2020 โ€ข 04:21 am 30 points
  • IIT JAM
  • Chemistry (CY)

I have sent u the question ...plz check that and i have also sent kinetic energy relation and radius..i used these relat.but i didn't got the answer...

The total ener9y TE. Potential Energy + Kinetic Enerqv rgy kze Potential energy P.E r Kinetic energy = mv T.E. =my? kZe r or From equation (3) mv kze r mv2 kze? 2r 1 = KE KE1 substituting this in equation (4) kze kze kze T.E. 2r =- KE 2r TE =-K.E T.E r

2 Answer(s) Answer Now
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  • Suman Kumar best-answer

    KE = (1/2)mv^2

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    mvr=nh/2ฯ€

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    solve this two you will definitely get

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    should I send you the solution

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    ya I know this

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    did you get then ?

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    ya

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    but

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    plz read the qiestion

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    I m saying different

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    you will solve the question according to the option na Sweta. Suppose you have two relation then you will have to solve according to the option

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    ๐Ÿ˜•

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    but answer to hmesha same aana Chahiye n

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    Answer will be definitely same. When you will solve 1/2 mv^2 = -kze^2/2r. See here we can find k.E in 2 ways with different data

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    yes

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    Priyanshu kumar Best Answer

    By direct relation you don't get answer??

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    means KE=1/2mv^2

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    and mvr =nh/2pi bohr postulate

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    relating this two relation

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    yes

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    sir

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    m saying that

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    this is kinetic energy I have marked

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    now in this substitute value of r

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    this r value

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    wait let me check....but here it is asking bohr orbit...so using bohr postulate of angular momentum you directly get

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    but let me check this also

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    these relations are also derived from Bohr or bit

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    wait shweta let me check it

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    Shweta here you get e^4 but in option it is not given na

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    jo diya hai uske according relation use krna hoga na...

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    this is also correct..no doubt

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    ok sir got it

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    ๐Ÿ˜Š๐Ÿ‘

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    app is not working properly ๐Ÿ™

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    I know

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    sir

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    sir

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    sir

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    yes

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    I didn't get the answer for my next question

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    yes shweta searching for some video...which helps u...as it can be explain easily in copy but takes time

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    ok sir

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