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Shweta Thakur posted an Question
January 28, 2021 • 05:59 am
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30 points
30 points
- IIT JAM
- Chemistry (CY)
I have solve the question so please explain the book solution only f steam at 100°c 373 7x 22400=30605 ml. kvolume of 1 mole of water at 10
alclti0f1s 1ons Modern Approach 416 =1-013 x 10 dynes/cm2 C = 18 m. V=volume of 1 mole of steam at 100°C 373 7x 22400=30605 mL. Kvolume of 1 mole of water at 100°C 16 vol. 0 wot ad oo Chare Now we have, W=-p(V2- V) = -1-013 x 10° x (30605 - 18) ergs -1-013 x 10° x 30587 calories 4-18x 10 -741 calories. Again we have,
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Suman Kumar
What is your doubt
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During phase transition from solid to gas at 100-degree celcius water is gas at point B & liquid at point C
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I am not getting how they have taken volume of water at 0 degree Celsius is 22.4 litre......s see the charlrs law which they have used#
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yes Charles law sahi hai
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Amol ashok pawar![best-answer]()
First of all for pressure units are converted to cms Then volume of one mole H2O (1*2+16=18)ml is taken Then for steam (which is in gaseous state) conversion are made 0 to 100 with STP volume 22.4(which is further converted into cms units by multiplying by 1000 Them simply substituting the value in the equation We will get the answer
sir here m only confused in Charles law which they have used to find the volume of steam at hundred degree Celsius
they have they have taken volume of water at 0 degree Celsius is 22.4 litres
is it so??
plz explain sir
at 0C 22.4l of gas is required to be frozen to get a gram equivalent (18g)of water. I think your confusion has raised due to gaseous and liquid phase differences. don't worry for exam purposes just remember the factor 22.4 so it will be useful to solve the question.
ok sir
thanku