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Shweta thakur Asked a Question
January 28, 2021 12:29 ampts 30 pts
  • IIT JAM
  • Chemistry (CY)

I have solve the question so please explain the book solution only f steam at 100°c 373 7x 22400=30605 ml. kvolume of 1 mole of water at 10

alclti0f1s 1ons Modern Approach 416 =1-013 x 10 dynes/cm2 C = 18 m. V=volume of 1 mole of steam at 100°C 373 7x 22400=30605 mL. Kvolume of 1 mole of water at 100°C 16 vol. 0 wot ad oo Chare Now we have, W=-p(V2- V) = -1-013 x 10° x (30605 - 18) ergs -1-013 x 10° x 30587 calories 4-18x 10 -741 calories. Again we have,
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  • Amol thankyou
    First of all for pressure units are converted to cms Then volume of one mole H2O (1*2+16=18)ml is taken Then for steam (which is in gaseous state) conversion are made 0 to 100 with...
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    Shweta thakur
    sir here m only confused in Charles law which they have used to find the volume of steam at hundred degree Celsius
  • Suman Kumar
    What is your doubt
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    Suman Kumar
    During phase transition from solid to gas at 100-degree celcius water is gas at point B & liquid at point C
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