I m getting answers as b

cross Aldol & self Aldol

cannizaro nahi hoga kyun?

cannizaro to ho hi nahi sakta kyonki Alpha must be absent for cannizaro reaction

Dusri baat Hydride transfer aise bhi little difficult hoti hai alpha hydrogen nahi hoga tabhi cannizaro hi payega

base agar benzaldehye mai attack karega?

benzaldehye to show kr sakta hai na cannizaro

sir?

are bola to Alpha proton must be absent. This is the necessary condition. Because Hydride transfer easy hote hai. It is RDS step

For cannizaro reaction we take higher concentration of NaOH

idhar ye pdt nai ho skte kya? benzaldehye mai to alpha hydrogen nahi hai

Are yaar but reactant sirf benzaldehyde hai ?

ok.. to yahan cannizaro product possible nahi hain

Bilkul nahi

must condition: alpha hydrogen should be absent for cannizaro

why

it said excluding stereo

total four

C6H5CHO is ont formed self condensed product with base...not aldol

sir it is saying without give answer without steroisomers..plz check

C6H5CHO can form canizzaro product na?

...

including stereo chemistry it is 4....excylded it is 2

but we can also form cannizzaro product

yes...only with C6H5CHo and naoh...it canform canizzaro products

but ch3cho is given hence it can give aldol product also

so there should be cannizaro products also

also these products should be formed na?

presence of naoh with ch3cho give enolate..

but if we follow cannizaro method acid and alcohol are formed na?

..

so how many products should be formed?

four...2 aldol...acid and alcohol..

yes sir.. but answer given as 2 product formed

if only C6H5CHo is one reactant it follows canizzaro with naoh.....but given ch3cho and C6H5CHo give only two products (exculdeded stereochemistry)

cannizaro product won't happen?

aldol dominate canizzaro...due to aldehyde reactivity