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Sourav posted an Question
September 13, 2020 • 16:27 pm 30 points
  • IIT JAM
  • Chemistry (CY)

I m getting answers as b

. Number of products (excluding stereoisomers) in the given reaction: CH CHO +CH-CHOÕH Product will be a) (b) Three c)Two ) Four One

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  • Suman Kumar Best Answer

    Here 2 product will be formed

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    cross Aldol & self Aldol

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    cannizaro nahi hoga kyun?

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    cannizaro to ho hi nahi sakta kyonki Alpha must be absent for cannizaro reaction

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    Dusri baat Hydride transfer aise bhi little difficult hoti hai alpha hydrogen nahi hoga tabhi cannizaro hi payega

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    base agar benzaldehye mai attack karega?

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    benzaldehye to show kr sakta hai na cannizaro

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    sir?

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    are bola to Alpha proton must be absent. This is the necessary condition. Because Hydride transfer easy hote hai. It is RDS step

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    For cannizaro reaction we take higher concentration of NaOH

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    idhar ye pdt nai ho skte kya? benzaldehye mai to alpha hydrogen nahi hai

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    Are yaar but reactant sirf benzaldehyde hai ?

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    ok.. to yahan cannizaro product possible nahi hain

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    Bilkul nahi

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    must condition: alpha hydrogen should be absent for cannizaro

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    Boddu rama krishna best-answer

    two

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    why

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    it said excluding stereo

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    total four

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    C6H5CHO is ont formed self condensed product with base...not aldol

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    sir it is saying without give answer without steroisomers..plz check

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    C6H5CHO can form canizzaro product na?

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    ...

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    including stereo chemistry it is 4....excylded it is 2

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    but we can also form cannizzaro product

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    yes...only with C6H5CHo and naoh...it canform canizzaro products

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    but ch3cho is given hence it can give aldol product also

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    so there should be cannizaro products also

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    also these products should be formed na?

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    presence of naoh with ch3cho give enolate..

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    but if we follow cannizaro method acid and alcohol are formed na?

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    ..

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    so how many products should be formed?

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    four...2 aldol...acid and alcohol..

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    yes sir.. but answer given as 2 product formed

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    if only C6H5CHo is one reactant it follows canizzaro with naoh.....but given ch3cho and C6H5CHo give only two products (exculdeded stereochemistry)

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    cannizaro product won't happen?

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    aldol dominate canizzaro...due to aldehyde reactivity

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