profile-img
Vanshika Asked a Question
September 1, 2020 10:33 ampts 30 pts
The frequency of the photon produced when an electron of 20 keV is brounht collision with a heavy nucleus is 2. (in term of 1018 Hz).
  • 2 Answer(s)
  • 0 Likes
  • 3 Comments
  • Shares
  • Ruby negi Best Answer
    as total energy of electron is used to eject photon so u can directly equate energy of photon Is equal to given k.e of electron...
    • cropped222308748.jpg
    Likes(0) Reply(0)
  • Chandra dhawan thankyou
    see attachment dear ..
    • cropped4850613561736878583.jpg
    Likes(1) Reply(1)
    Chandra dhawan
    it will be helpful
  • Vaishnavi rajora
    E = 20 Kev .........(1) also E = hv ( v = frequency) = 20 Kev ........(2) Now from eqn (1) & (2) v = 4.8 × 10^18 Hz
    Likes(1) Reply(1)
    Vaishnavi rajora
    hope it'll help you