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Vanshika Asked a Question
September 1, 2020 10:33 ampts 30 pts
  • IIT JAM
  • Physics (PH)

I used this formula to solve this question is it correct but my ans is coming different.

The frequency of the photon produced when an electron of 20 keV is brounht collision with a heavy nucleus is 2. (in term of 1018 Hz).
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  • Ruby negi Best Answer
    as total energy of electron is used to eject photon so u can directly equate energy of photon Is equal to given k.e of electron...
    • cropped222308748.jpg
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  • Chandra dhawan thankyou
    see attachment dear ..
    • cropped4850613561736878583.jpg
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    Chandra dhawan
    it will be helpful
  • Vaishnavi rajora
    E = 20 Kev .........(1) also E = hv ( v = frequency) = 20 Kev ........(2) Now from eqn (1) & (2) v = 4.8 × 10^18 Hz
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    Vaishnavi rajora
    hope it'll help you
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