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If the radius and height of a cone are each increased by 100%, by what percentage does the volume of the cone increase? The volume of a cone isV = (1/3)(pi)R^2h. Let the original cone have a radius of 1m and height of 1m. Then its volume V1 = (1/3)(pi)(1^2)(1) or (1/3)(pi)*(1). If the radius and height are increased by 100%, the radius becomes 2m and the height 2m. In this case the volume of the cone V2 = (1/3)(pi)(2^2)(2) or (1/3)(pi)*(8). Divide V2 by V1 to get 8. Therefore the volume increases to 800% if the radius and height are increased by 100%. The net increase in volume of the cone on doubling its radius and the height is 800%-100% = 700%.