If the recessive disease phenylketonuria (pku) occurs in a genetically constant population with a frequency of 1 in 1o000, the frequency of the carrier genotype

We that from Hardy-Weinburg principle that : p+q = 1 Here p = Dominant q = Recessive Now here, q^2 = 1/10000 so, q = 1/100 Now, p = 1-q = 1- 1/100 = 99/100 so, p^2 = ...