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Dr. avtar chand Best Answer
adj(adjA)=|A|^(n-2).A A is orthogonal matric so det of A is 1 det of 2A²⁰ is 2³detA²⁰=8x(detA)²⁰=8 let B=2A²⁰ then det B =8 adj(adjB) is |B|B=8B det of adj(adjB) = 8³.8=8⁴=4096