In the reduction of hno3 to n2o,the number of mole of electrons involved per mole of hno3 is

HNO3​→0.5N2​O Oxidation number of nitrogen in HNO3​ and N2​O is +5 and +1 respectively so number of moles of electrons per mole of HNO3​ is 4.

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Oxidation number of nitrogen in HNO3​ and N2​O is +5 and +1 respectively so number of moles of electrons per mole of HNO3​ is 4.

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