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Umme Asked a Question
September 16, 2020 8:22 pmpts 30 pts
In the X-ray difiraction of a set of crystal planes havingd equal to 0.1 8 nm, frst order reflection is found to be at an angle of 22°. The wavelength of X-ray is: (sin 22=0.208): |BHU 2014] (a) 0.0749 nm (b) 0.0374 nm (c) 0.749 nm (d) 0.374 nm
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  • Chandra dhawan thankyou
    see attachment....
    • cropped3769463280688040261.jpg
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  • Somnath
    Use Bragg's law 2dSin(theta)=n(lamda) Now given d=0.18nm theta=22 degree for first order maximum n=1 lamda = 2dSin(theta) = 2×0.18×Sin22 ...
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  • Somnath thankyou
    Use Bragg's law 2dSin(theta)=n(lamda) Now given d=0.18nm theta=22 degree for first order maximum n=1 lamda = 2dSin(theta) = 2×0.18×Sin22 ...
    Show more
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  • Jeevesh Best Answer
    we have used the Bragg's law. please see the attachment for details.
    • cropped1651951502.jpg
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    Umme
    but what about the fact that sin 22° isn't 0.208 ...it's actually 0.3746
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