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Chandan Panigrahi posted an Question
October 14, 2020 • 22:17 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Is this complex inner field or outer field? and how?

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  • Suman Kumar Best Answer

    it is Inner orbital complex

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    how?

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    it is d2sp3.In exited state one of the 3d electrons of Co2+ (3d7) transfers into 5s orbital and the other 6 electrons of 3d orbital pair and remain in 3, 3d orbitals.dx^2-y^2 & dz^2 remain empty.Then 2 inner 3d, one outer 4s & 3 outer 4p hybridize to form 6 equivalent d2sp3 hybrid orbital.Then 6 NH3 gives 6 electron pairs & create 6 coordinate bonds to form octahedral [Co(NH3)6]^2+ ion.It shows paramagnetic property as it has a unpaired electron in 5s orbital

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    sir how can i know in which complex the electron excite into 5s orbital and in which case it doesnt excite?

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    this is an rare example

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    it's proof is that it's oxidation potential is very high i.e it can easily lose its eletron

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    Co² = Co³+ +e due to Eletron in 5s

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    tq sir😇😇

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    Priyanshu kumar best-answer

    In [Ni(NH3)6]2+, Ni is in +2 state and has configuration 3d8. In presence of NH3, the 3d electrons do not pair up. The hybridization is sp3d2 forming an outer orbital complex.

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    sir i am asking about Co as central metal atom not Ni

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    co(nh3)6 2+ is inner orbital

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    sorry and thanks for correcting

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    here hybrisation in d2sp3 octahedral complex

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    sir but thare are 7 electron if they pair than also thare is a unpair electron present than how it is d2sp3?

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    see

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    1 unpaired is present and it is paramagnetic but it excites from 3d to 5s

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    and it is experimentally evidence that it form inner orbital complex with one unpaired electrons in 5s orbitals

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    sir in all the case one electron is excitee in 5s or thare are some specific complex?

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    rare exceptions are there and by practicing it comes

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    okk sir tqq

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