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Shweta Thakur posted an Question
August 11, 2020 • 22:34 pm
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30 points
30 points
- IIT JAM
- Chemistry (CY)
It's answer is 2to 5 bohr series of line of hydrogen spectrum, third line from the red end cbit in atom o
In Bohr series of line of Hydrogen spectrum, third line from the red end corresponds to which o of the following inner orbit jumps of e for Bohr orbit in atom of Hydrogen ? (a) 41 (b) 25 (c) VIBGYOR region 32 (d) 52
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Priyanshu kumar Best Answer
yes shweta it is right... transition from 5-2
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Red means its a part of visible region. Balmer series corresponds to visible region. In balmer series n1=2 third line means n2-n1 =3 so n2 =3+2=5. So transition is 5-2
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got it shweta??
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2 to 5 is the answer n ..b option
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absorption from 2-5;and emission from 5-2..here electrons jumps from higher to lower so emission and transition from 5-2..so that 3 lines comes
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now got it shweta??
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yes sir
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😊👍👏
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Priyanshu kumar
Hope this will helps u😊