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Shweta thakur Asked a Question
August 11, 2020 5:04 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

It's answer is 2to 5 bohr series of line of hydrogen spectrum, third line from the red end cbit in atom o

In Bohr series of line of Hydrogen spectrum, third line from the red end corresponds to which o of the following inner orbit jumps of e for Bohr orbit in atom of Hydrogen ? (a) 41 (b) 25 (c) VIBGYOR region 32 (d) 52
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  • Priyanshu kumar Best Answer
    yes shweta it is right... transition from 5-2
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    Priyanshu kumar
    Red means its a part of visible region. Balmer series corresponds to visible region. In balmer series n1=2 third line means n2-n1 =3 so n2 =3+2=5. So transition is 5-2
  • Dinesh khalmaniya thankyou
    (d) The emission is in visible (VIBGYOR)(VIBGYOR) region. Thus Balmer series i.e., either (c)(c) or (d)(d). In ( c) only one emission. The third line will be in the junp from 55 to...
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    Dinesh khalmaniya
    video Solution https://youtu.be/HWfAHWFXb4U
  • Priyanshu kumar
    Hope this will helps ušŸ˜Š
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