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Deepak patra Asked a Question
October 17, 2021 5:22 pmpts 30 pts
-Le A be a 4x4 inveztfble real matex. hich he ollocdtng is NOT oue ? (necessabila he ous o A fovm a basis of I Nul Space contas only fHe o recto A has distfnct eigen Ynluos mage T= Ax is I
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  • Deepak patra
    no option b is correct .. as T is one one , only zero vector will map to zero vector of range space... no other than zero vector will map to zero..
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  • Navdeep goyal 1
    A is 4×4 invertable matrix therefore rank of A is 4 or its nullity is zero (nullity= order- rank =4-4=0)so null space contain only zero vector so options B true
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  • Navdeep goyal 1 thankyou
    C is not true we know that prodect of eigen values equal to determinate of matrix A. example if egien values 1,1,2,3 then determinate of A is 6 so A is invertable.
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    Anku 1
    sir just i wanted to ask isn't option b false..?
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