Saurabh Asked a Question
June 10, 2022 10:45 ampts 10 pts
Let A = (aij) be a 10 x 10 matrix such that aij=1 for i≠ j and aii= α + 1, where α > 0. Let λ and μ be the largest and the smallest Eigenvalues of A, respectively. If λ+μ = 24, then α equals
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  • Navdeep goyal 1 thankyou
    maximum eigen value sum of all row elements a+1+9 and minimum a+1-1 so a+10+a=24 2a=14 a=7
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    Saurabh
    a+a+10=24 where a is smallest ev and a+10 is largest ev so, 2a=24-10= 14 => a= 7 and a+10=17