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Deepak patra Asked a Question
November 15, 2021 4:44 pmpts 30 pts
Let f:[0, 1]->[0,1 be continuous and S(0)=0,S(1)=1. Then, f is necessarily (a.) injective, but not surjective. (6.) surjective, but not injective. (c.) bijective. (d.) surjective.
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  • Deepak singh 1 Best Answer
    Refer attachment option d
    • cropped3142670880350049953.jpg
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