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Vijay Singh chauhan Asked a Question
October 6, 2020 5:41 pmpts 30 pts
  • IIT JAM
  • Mathematics (MA)

Let f: r> r be a constant function. then image of r under f is: (a) open (b) not open (c) empty (d) infinite.

Let f: R> R be a constant function. Then image of R under f is: (a) open (b) not open (C) empty (d) infinite.
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  • Jagat Chaudhary thankyou
    yes option (b) correct. for a constant function
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  • Deepak singh Best Answer
    since constant function is finite , So can't be open.. because for openness , uncountablity is necessary condition. thus option b is correct if any doubt then ask
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    Vijay Singh chauhan
    Thank you sir for helping in clearing my doubts.
  • Vishal goswami
    option b is correct
    Likes(0) Reply(0)
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