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Vijay posted an Question
October 06, 2020 • 23:16 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Let f: r r be a constant function. then image of r under f is (a) open (b) not open ()empty (d) infinite.

Let f: R R be a constant function. Then image of R under f is (a) open (b) not open ()empty (d) infinite.

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    Deepak singh 1 Best Answer

    option b is correct since constant function is finite , So can't be open. if any doubt then ask

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    because for openness , uncountablity is necessary condition

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