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Vijay Singh chauhan Asked a Question
October 6, 2020 5:46 pmpts 30 pts
  • IIT JAM
  • Mathematics (MA)

Let f: r r be a constant function. then image of r under f is (a) open (b) not open ()empty (d) infinite.

Let f: R R be a constant function. Then image of R under f is (a) open (b) not open ()empty (d) infinite.
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  • Deepak singh Best Answer
    option b is correct since constant function is finite , So can't be open. if any doubt then ask
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    Deepak singh
    because for openness , uncountablity is necessary condition
  • Vishal goswami
    option b is correct
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