Ankur posted an Question
January 11, 2021 • 22:25 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Let f: r:r>r be defined by f(t)=t and let u be any non-empty open subset of r then f(u) is open s(u)is open may be closed o(u) may be osed

Let f: R:R>R be defined by f(t)=t and let U be any non-empty open subset of R then f(U) is open S(U)is open may be closed O(U) may be osed

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    Piyush pachauri

    Option AB is correct. Continuity implies both

    eduncle-logo-app

    continuity doesn't implies 1st

  • Anonymous User

    bcoz under continuity inverse image of an open set is always an open set

    eduncle-logo-app

    option A

    eduncle-logo-app

    option A is correct for this question. but in general it's not true that under continuity image of an open set is an open

  • Anonymous User

    For option B visit the following link. 1. https://math.stackexchange.com/questions/843909/prove-that-the-inverse-image-of-an-open-set-is-open

    eduncle-logo-app

    which of options is correct in this sir

    eduncle-logo-app

    are 3rd and 4th true

    eduncle-logo-app

    option B is correct

    eduncle-logo-app

    A is not correct

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