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## Anonymous User Best Answer

9. f(x)=[x] is discontinue at x=n for all n€Z so f(x)=[x²] is discontinue at x²=n=> x=±√n for all n€N 10 monotonic fun always continus 11 b f is discontinus at 0,1 bcz f(0+)=1 f(0-)=0 and f(1+)=0 f(1-)=1

sir, will you please send the solutions of question no. 12, 14, 15, 16, 17, 18